Question

find zeroes of the polynomial x²-2x-8​

Answer 1

Answer:

X= -2 and X = 4

Step-by-step explanation:

x2-(4-2)x-8

x2-4x+2x-8

(x2-4x)+(2x-8)

X(x-4)+2(x-4)

X+2&x-4

therefore X= -2 and X = 4

Answer 2

Answer:

roots are 4 and -2

Step-by-step explanation:

we can solve this by using factorisation method.

x^2-2x-8 = 0

product of numbers should be -8

sum of numbers should be -2

obviously, the two numbers are -4 and 2

now we have to write in the equation as follows:

x^2-4x+2x-8 = 0

take common,

x(x-4)+2(x-4) = 0

(x+2)(x-4). = 0

x+2 = 0 and x-4 = 0

hence,

x = -2 and x = 4.( by transforming 2 and -4 to RHS)

and we found that the equation have two roots:

{-2 and 4}