find zeroes of the polynomial x⁴+3x³-7x²-27x-18
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If α and B are two roots of f(x) then (x−α) and (x−B) are two factors of the given polynomial.
Thus, (x−α)(x−β)=(x+3–√)(x−3–√)=x2−3 divides f(x).
x4−3x3−x2+9x−6x2−3
=x2−3x+2 (by division method).
Now, only task remained is to factorise x2−3x+2.
x2−3x+2=(x−1)(x−2).
Therefore, other roots are :
x=1 and x=2.
Hope this help you ;
Bhavy Yadav
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