Question

Find zeroes of the quadratic polynomial 4s^2 - 4s + 1

Answer 1

Hi...☺

Here is your answer...✌

Let p(s) = 4s² - 4s + 1

To find zero ,we put

p(s) = 0

4s² - 4s + 1 = 0

4s² - 2s - 2s + 1 = 0

2s ( 2s - 1 ) -1 ( 2s - 1 ) = 0

(2s - 1) (2s - 1) = 0

=> s = 1/2

Answer 2

4s^2 - 4s + 1
4s^2 -2s - 2s +1
2s (2s - 1) -1 (2s - 1)
2s - 1 = 0. & 2s - 1 = 0.
s = 1/2. & s = 1/2.
So, zero of equation is 1/2