find zeroes of x2-9x+20 and verify relation between zeroes and co efficient
swetha05:
please solve it
x2= x^2 ha
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x² - 9x + 20 = 0
x² - 4x - 5x + 20 = 0
x(x-4) - 5(x-4) = 0
(x-4)(x-5) = 0
x-4 = 0 | x-5 = 0
x = 4 | x = 5
Therefore,the zeroes of the polynomial are 4 and 5.
Relation between zeroes and coefficients:-
»Sum of zeroes = 4+5
= 9 = -(-9) = -x coefficient/x² coefficient
»Product of zeroes = 4 × 5
= 20 = constant/x² coefficient
Hope it helps…
x² - 4x - 5x + 20 = 0
x(x-4) - 5(x-4) = 0
(x-4)(x-5) = 0
x-4 = 0 | x-5 = 0
x = 4 | x = 5
Therefore,the zeroes of the polynomial are 4 and 5.
Relation between zeroes and coefficients:-
»Sum of zeroes = 4+5
= 9 = -(-9) = -x coefficient/x² coefficient
»Product of zeroes = 4 × 5
= 20 = constant/x² coefficient
Hope it helps…
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