Question

find zeroes (x^2/a)+(b/ac) *(-x/b) - (1/c) ​

Answer 1

Answer:

c x ^ 2 - c ^ 2 x - a / a c

Step-by-step explanation:

( x ^ 2 / a ) + ( b / a * c ) * ( - x / b ) - ( 1 / c )

( x ^ 2 / a ) + ( b / a * c ) * ( - x / b ) - ( 1 / c )

x ^ 2 / a + b c / a * - x / b - 1 / c

x ^ 2 / a - b c / a * x / b - 1 / c

x ^ 2 / a - c / a * x - 1 / c

x ^ 2 / a - c x / a - 1 / c

c x ^ 2 - c ^ 2 x - a / a c

Answer 2

STEP BY STEP EXPLANATION:

(x^2/a)+(b/*c) *(-x/b) - (1/c)

x 2/a -bc/a*-x/b -1/x

x2/a-bc/a*x/b-1/c

x^2/a-c/a*x-1/c

x^2/a-c x / a - 1 /c

cx^2-c^2x-a/ a c

HOPE IT MAY HELPS YOU!