Find zeros 3x^2 -2 √6x + 2
Answers
Answered by
1
Answer:
The answer is x= root2/3, x= root 2/3
Answered by
0
Answer:
root2/3
Step-by-step explanation:
We will have to factorise this polynomial to find the zeroes.
3x^2 - 2 root6 x + 2
= 3x^2 - root6 x - root6x +2
= 3x(x - root2/3) - root6(x - root2/3)
= (x - root2/3) (3x - root6)
Now, taking the value of each factor as 0, we get that,
x - root2/3 = 0
x = root2/3
3x - root6 = 0
3x= root6
x = root6 ÷ 3 = root2/3
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