Question

Find zeros of:- 4x^2-4x+1=0

Answer 1

Answer:

1/2

Step-by-step explanation:

4x²-4x+1= 4x²-2x-2x+1

= 2x(2x-1)-1(2x-1)

= (2x-1)(2x-1)

There is only one zero, and it is 1/2

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Answer 2

Answer:

zeroes of the given polynomial are 1/2 and 1/2

Step-by-step explanation:

Given that:

4x^2-4x+1=0

=>(2x)^2-2(2x)(1)+(1)^2=0

=>(2x-1)^2=0 ...(it is in the form of (a-b)^2)

(a-b)^2=a^2-2ab+b^2

=>(2x-1)(2x-1)=0

=>2x-1=0 or2x-1=0

=>2x=1

=>x=1/2 and 1/2