Question

find zeros of p(x) 2 x ^ - 1 X - 6 and verify the relationship between zero​

Answer 1

Step-by-step explanation:

p(x)=2x^2-x-6

=2x^2-4x+3x-6

=2x(x-2)+3(x-2)

=(2x+3)(x-2)

x= -3/2 or 2

Sum of roots= -b/a= -(-1)/2

product of roots= c/a= -6/2= -3

Sum of roots= -3/2+2= 1/2

Product of roots= -3/2*2= -3

Hence verified....