Question

If the initial of an ideal gas at 2.250 atm is 62.00°c, what final temperature would cause the pressure to be reduced to 1.750 atm?

Answer 1

Using Gay-Lussac's Law, we have P1/T1 = P2/T2

We have P1 = 2.25 atm

T1 = 62 C = 335 K

P2 = 1.65 atm

So T2 = P2 /(P1/T1) = (1.65 / (2.25/335))=245.7 K = -27.3 C

Answer 2

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