Question

Find zeros of p(x) =2s^2-(1+2√2)s+√2 by factorisation method.

Answer 1

Heya user
Here is your answer !!

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2s^2 - ( 1 + 2√2 )s + √2
=> 2s^2 - 1s - 2√2s + √2
=> s ( 2s - 1 ) - √2 ( 2s - 1 )
=> ( s - √2 ) ( 2s - 1 ) .

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So , the zeroes of p(x) are ----->
s = √2
and ,
s = 1/2 .

Hope it helps !!