Question

find zeros of polynomial √3x2-8x+4√3

Answer 1

Answer:

Given quadratic equation = √3x² - 8x + 4√3 = 0

We should factorize the equation first.

         =√3x²-6x-2x+4√3 = 0

         = √3x(x-2√3)-2(x-2√3) = 0 

         = (√3x-2) (x-2√3) = 0

         = (√3x-2) = 0 , (x-2√3) = 0

         = x = 2/√3 , x = 2√3.

Answer 2

$\huge\bold\pink{ANSWER:}$

Hello Dear User__________

Here is Your Answer...!!

____________________

Step by step solution:

$Given \ p(x)=\sqrt{3} x^2-8x+4\sqrt{3}\\\\we \ have \ to \ solve \ it.\\\\Let \ us \ do\\\\p(x)=\sqrt{3} x^2-6x-2x+4\sqrt{3} \\\\p(x)=\sqrt{3} x(x-2\sqrt{3} )-2(x+2\sqrt{3} )\\\\p(x)=(x-2\sqrt{3} )(\sqrt{3} x-2)\\\\for \ zeroes \ x-2\sqrt{3} =0 \ or \ \sqrt{3} x-2=0\\\\x=2\sqrt{3} \ or \ x=\frac{2}{\sqrt{3} }=\frac{2\sqrt{3} }3}$

Hope it is clear to you.