find zeros of polynomial 8y-3y
Answers
Answered by
0
Answer:
5y
Step-by-step explanation:
Answered by
1
Answer:
Step-by-step explanation:
Let m and n be the zeroes.
p(x) = 8y² - 3y
8y² - 3y = 0
y (8y-3) =0
y = 0 or y = 3/8
Let m=0 and n= 3/8
Now,
m + n = - b/a
0 + 3/8 = (-3/8)
3/8 = 3/8
Also,
mn = c/a
0× 3/8= 0 /8
0 =0
Hence the relation between zeroes and coefficient is verified.
Similar questions