Question

Find zeros of Polynomial p(x)=3x²-x-4 and verify relation between zeros and cofficient​

Answer 1

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❤️❤️ꀍꏂꋪꏂ ꀤꌚ ꀎꍏ ꍏꈤꌚꅐꏂꋪ❤️❤️

$zeroes \: are \\ 3{x}^{2} - x - 4 = 0 \\ {3x}^{2} + 3x - 4x - 4 = 0$

$3x(x + 1) - 4(x + 1) = 0 \\ (x + 1)(3x - 4) = 0$

$therefore \: \: x \: is \: equal \: to \: either \: \\ - 1or \frac{4}{3}$

$sum = - 1 + \frac{4}{3} = - 3 + \frac{4}{3} = \frac{1}{3} \\ sum = - \frac{b}{a} = \frac{1}{3}$

$product = - 1 \times \frac{4}{3} = \frac{ - 4}{3} \\ product = \frac{c}{a} = \frac{ - 4}{3} \\ hence \: proved$

Answer 2

REFER TO THE ATTACHMEMT

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