Question

find zeros of polynomial X square + 17 X + 10 solve this properly

Answer 1

☆Hey friend!!! ☆

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Here is your answer ☞
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given, polynomial

=> X²+17X+10=0

Here,

{a=1, b=17 and c=10}

Now

$= > x = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ = > x = \frac{ - 17 \binom{ + }{ - } \sqrt{ {17}^{2} - 4 \times 1 \times10 } }{2} \\ \\ = > x = \frac{ - 17 \binom{ + }{ - } \sqrt{ 289 - 40 } }{2} \\ \\ = > x = \frac{ - 17 \binom{ + }{ - } \sqrt{249} }{2} \\ \\ = > x = \frac{ - 17 \binom{ + }{ - } 15.78}{2} \\ \\ = > x = \frac{ - 17 + 15.78}{2} \: \: \: or \: \: x = \frac{ - 17 - 15.78}{2} \\ \\ = > x = 0.61 \: \: \: \: \: or \: \: \: \: \: \: x = - 16.39$

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Hope it will help you ☺☺☺
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Devil_king ▄︻̷̿┻̿═━一