Question

Find zeros of polynomial x²-3 and verify the relationship between zeros and the coefficients​

Answer 1

Answer:

Given polynomial is x^2 - 3.

a = 1, b = 0, c = - 3.

x^2 - 3 = ( x - √3 ) ( x - √3 ).

The value of x^2 - 3 is zero.

x = √3 or x = - √3.

The zeroes of x^2 - 3 are √3 and -√3.

Sum of zeroes = √3 - √3 = 0 = 0/1 = -b/a.

Product of zeroes = (√3) (-√3) = - 3 = -3/1 = c/a.

Hence verified.

Step-by-step explanation:

I HOPE YOU UNDERSTAND NOW.