Question

Print the pattern shown in the attachment using python loop.

Answer 1

$\texttt{\textsf{\large{\underline{Solution}:}}}$

The given co‎de is written in Python.

n=3 # Rows = Columns

for i in range(1,n+1):

 for j in range(1,n+1):

   if i==1 or j==1 or i==n or j==n:

     print("* ",end="")

   else:

     print("  ",end="")

 print()

Here, n stores the number of rows for the pattern. Here, I gave four conditions. If any of the conditions is satisfied, star is printed or else, spaces are added. A new line is inserted after that.

Answer 2

Answer:

The given co‎de is written in Python.

n=3 # Rows = Columns

for i in range(1,n+1):

 for j in range(1,n+1):

   if i==1 or j==1 or i==n or j==n:

 print("* ",end="")

  else

print("  ",end="")

 print()

Here, n stores the number of rows for the pattern. Here, I gave four conditions. If any of the conditions is satisfied, star is printed or else, spaces are added. A new line is inserted after that.

Explanation:

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