Question

find zeros of quadratic polynomial
5x² - 2 root 5x - 3
and verify the relationship​

Answer 1

$5x^{2} - 2\sqrt{5x} -3\\= 5x^{2} + \sqrt{5x} - 3 \sqrt{5x} - 3 \\= \sqrt{5x} ( \sqrt{5x} + 1) -3( \sqrt{5x} + 1)\\ = (\sqrt{5x} - 3)(\sqrt{5x} + 1)\\= x = \frac{3}{\sqrt{5} } , x = -\frac{1}{\sqrt{5} }$

Sum of zeroes =  $\frac{3}{\sqrt{5} } - \frac{1}{\sqrt{5} } = \frac{2}{\sqrt{5} }$  

Sum of roots = $\frac{-b}{a} =$ $\frac{2\sqrt{5} }{5} = \frac{2}{\sqrt{5} }$

Product of zeroes = $\frac{3}{\sqrt{5} } X -\frac{1}{\sqrt{5} } = -\frac{3}{5}$

Product of roots= $\frac{c}{a} =\frac{-3}{5}$

Hence verified.

Mark as brainliest!!!!!!!!!!!

Answer 2

Step-by-step explanation:

=5x(5x+1)−3(5x+1)=(5x−3)(5x+1)=x=53,x=−51

Sum of zeroes =  \frac{3}{\sqrt{5} } - \frac{1}{\sqrt{5} } = \frac{2}{\sqrt{5} }53−51=52  

Sum of roots = \frac{-b}{a} =a−b= \frac{2\sqrt{5} }{5} = \frac{2}{\sqrt{5} }525=52

Product of zeroes = \frac{3}{\sqrt{5} } X -\frac{1}{\sqrt{5} } = -\frac{3}{5}53X−51=−53

Product of roots= \frac{c}{a} =\frac{-3}{5}ac=5−3

Hence verified.

Mark as brainliest!!!!!!!!!!!