Find zeros of quadratic polynomial3xsquare -x-4
Answers
Answered by
2
3x²-x-4=0
=> 3x²-4x+3x-4=0
=> x(3x-4)+1(3x-4)=0
=> x+1=0 and 3x-4 = 0
=> x=-1 and x=4/3
=> 3x²-4x+3x-4=0
=> x(3x-4)+1(3x-4)=0
=> x+1=0 and 3x-4 = 0
=> x=-1 and x=4/3
Answered by
1
Hey
Here is your answer,
3x^2 - x - 4=0
3x^2 -3x+4x-4=0
3x(x-1) +4(x-1) =0
(X-1) (3x+4) =0
X-1=0
X=1
3x+4=0
X=-4/3
Hope it helps you!
Here is your answer,
3x^2 - x - 4=0
3x^2 -3x+4x-4=0
3x(x-1) +4(x-1) =0
(X-1) (3x+4) =0
X-1=0
X=1
3x+4=0
X=-4/3
Hope it helps you!
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