find zeros of the following
2s²-(1+2√2)s+√2
Answers
Answered by
16
hi friend,
f(s)=2s²-(1+2√2)s+√2
= 2s²-s-2√2s+√2
=s(2s-1)-√2(2s-1)
=(s-√2)(2s-1)
so,√2,1/2 are the zeros of the given polynomial.
I hope this will help u ;)
♥dhathri123♥
f(s)=2s²-(1+2√2)s+√2
= 2s²-s-2√2s+√2
=s(2s-1)-√2(2s-1)
=(s-√2)(2s-1)
so,√2,1/2 are the zeros of the given polynomial.
I hope this will help u ;)
♥dhathri123♥
Answered by
8
Hey there !
f(s) = 2s²-(1+2√2)s+√2
opening the brackets :-
2s²-s - 2√2s+√2
s(2s-1) - √2(2s-1)
(s-√2) (2s-1)
Hence ,
√2, 1/2 are the zeros of the given polynomial.
f(s) = 2s²-(1+2√2)s+√2
opening the brackets :-
2s²-s - 2√2s+√2
s(2s-1) - √2(2s-1)
(s-√2) (2s-1)
Hence ,
√2, 1/2 are the zeros of the given polynomial.
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