Find zeros of the polynomials z^2-8
Answers
Answered by
18
z^2-(2√2)^2
=(z+2√2)(z-2√2)
do zeroes of polynomial=-2√2 &2√2
Hope it will help you
=(z+2√2)(z-2√2)
do zeroes of polynomial=-2√2 &2√2
Hope it will help you
Answered by
13
Answer:
Step-by-step explanation:
z^2-8=0
z^2-(2√2)=0
z-2√2=0,Z+2√2=0
Z=2√2,Z=-2√2
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