Findbthe value of a+b+c+d.If the product of first 10 natural numbers is written as 2^a×3^b×5^c×7^d
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a=3
b=1
c=1
d=0
2^{3} 3^{1} 5^{1} 7^{0}=8x3x5x1=120
the product of first 10 natural numbers is 120
b=1
c=1
d=0
2^{3} 3^{1} 5^{1} 7^{0}=8x3x5x1=120
the product of first 10 natural numbers is 120
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