Finding sum of n terms in AP using geometrical method with proof
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In an AP
where
First term = a
difference = d
Sum = S
nth term = a(n)
Thus
a(n) = a + (n-1)d
And
S = n/2 [ 2 + (n-1)d
where
First term = a
difference = d
Sum = S
nth term = a(n)
Thus
a(n) = a + (n-1)d
And
S = n/2 [ 2 + (n-1)d
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