Question

finding value of a normal variable n=16=2=25 =26​

Answer 1

answer:

Example 20 What is the smallest positive integer n, for which (1 + i)

2n

= (1 – i)

2n?

Solution n = 2, because

2n = 1which is possible if n = 2 (∴ i

4

= 1)

Example 21 What is the reciprocal of 3 + 7 i

Solution Reciprocal of z = 2

z

z

Therefore, reciprocal of 3 + 7 i =

3 7 3 7

–

16 16 16

−

=

i i

Example 22 If z

1

= 3 + i 3 and z

2

= 3 + i , then find the quadrant in which

1

2

     

z

z

lies.

Solution

1

2

z

z

=

3 3 3 3 3 3

3 4 4

+ + −    

= +    

+    

i

i

i

which is represented by a point in first quadrant.