Findthe difference of air pressure between the inside and outside of a soap bubble 5mm in diameter in the surface tension is 1.6 N/ m
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Given: diameter(d)= 5mm
Therefore radius (r) = 2.5 mm or 0.25*10^-2m tension T = 1.6 N/m
Pi - Po = 4T/r
= 4 * 1.6/0.25*10^-2
= 4 * 160/ 1/4
= 2560N/meter sqr
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