Math, asked by ayushsinghyush8670, 11 months ago

Findthe value of 8sin2x.cos 4x.sin 6x, when x= 15°



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Answered by Anonymous
41
Hey, here is your answer....





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Answered by nayan81
13
8sin2x is= 8sin30°=8×1/2=4•
cos4x=cos4×15°=cos60°=1/2•
sin6x=sin90°=1
=4×1/2×1=2
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