Question

fine the HCF and LCM of 315 ,120 and 330 by applying prime factorization method
please answer this question???​

Answer 1

Correct question

• Find the LCM of 315,120 and 330 by applying prime factorization method.

Solution:

Step 1: To find LCM of 315, 120and 330 write each number as a product of prime factors.

$\tt : \longrightarrow315 = 3 \times 3 \times 5 \times 7 = \red{ 3^{2} \times 5 \times 7}$

$\tt: \longrightarrow \: 120 = 2 \times 2 \times 2 \times 3 \times 5 \\ \qquad \blue{= \tt \: {2}^{ 3} \times 3 \times 5}$

$\tt: \longrightarrow330 = \pink{2 \times 3 \times 5 \times 11}$

Step 2: Multiply all the prime factors with the highest degree.

Here we have 2 with highest power 3 and 3 with highest power 2

other prime factors 5, 7 and 11. Multiply all these to get LCM.

$\tt: \longrightarrow \: LCM_{(315,120and330)} = {2}^{3} \times {3}^{2} \times 5 \times 7 \times 11$

$\tt: \longrightarrow \: LCM_{(315,120and330)} = 27720$

____________________________

Correct question

• Find the LCM of 315,120 and 330 by applying prime factorization method.

Solution

step 1 : Find the prime factorization of 120 , 315 and 330

• 315 = 3 × 3 × 5 × 7

• 120 = 2 × 2 × 2 × 3 × 5

• 330 = 3 × 3 × 5 × 11

step 2 : To find the HCF, multiply all the prime factors common to both numbers:

Therefore,

$\tt: \longrightarrow \: HCF_{(315, 120 \: and \: 330)}=3 \times 5 = 15$

Answer 2

Answer:

refer to the above attachment