Math, asked by cphilip91, 11 months ago

fine the root of the equation 3y square +25y-13=0

Answers

Answered by dishabucha
2

Answer:

Step-by-step explanation:

3y² + 25y -13 = 0

A = 3 ,b = 25, c = -13

-b ± / b² - 4ac ÷ 2a

= -25 ± /(25)² - 4×3×(-13) ÷ 2×3

= -25 ± / 625 + 156 ÷ 6

= -25 ± / 781 ÷ 6

X = -25 + /781 ÷ 6

X = -25 - /781 ÷ 6

Hope it works

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