Question

finf 3by 7+(-5by14)+(-9by14)(5by7
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Answer 1

Answer:

$5 + \frac{5}{14} + \frac{9}{14} + \frac{5}{7} \\ = \frac{5}{1} + \frac{5}{14} + \frac{9}{14} + \frac{5}{7} \\ = \frac{(5 \times 7) + 5}{14} + \frac{9}{14} + \frac{5}{7} \\ = \frac{45 + 5}{14} + \frac{9}{14} + \frac{5}{7} \\ = \frac{50}{14} + \frac{9}{14} + \frac{5}{7} \\ = \frac{50 + 9}{14} + \frac{5}{7} \\ = \frac{59}{14} + \frac{5}{7} \\ = \frac{59 + (5 \times 2)}{14} \\ = \frac{59 + 10}{14} \\ = \frac{69}{14}$