Question

Finf the roots of the polynomial n^2 -11n +24 = 0 ?

Answer 1

n^2 - 11n + 24

n^2 - 8n - 3 n + 24

n ( n - 8 ) - 3 ( n - 8 )

( n - 8 ) ( n - 3)

zeroes are :

n = 3 , n = 8

Answer 2

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⏩n² - 11n +24 = 0

⏩n² -8n -3n +24 = 0

⏩n(n -8) -3(n-8) =0

⏩(n-3)(n-8) =0

⏩by equating,

⏩n-3 = 0
⏩n = 3

⏩n-8 = 0

⏩n = 8

•°• Roots are 8 and 3

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