Question

Finf the value of k for which the system of equations kx+3y-3and 12x+ky=6 represents parallel lines

Answer 1

kx+3y-3=0........(I)
12x+ky-6=0.........(II)
By comparing I & II with equation ax+by+c=0
a1=k ; b1=3 ; c1=-3 ; a2=12 ; b2=k ; c2=-6

According to question,
=a1÷a2=b1÷b2 is not equal to c1÷c2
=k/3 = 3/k is not equal to-3/-6

For finding the value of k take the equal equation.
= k/3 = 3/k
= k×k=3×3
= k^2=9
= k=√9
= k=3
thus, the value of k is 3.