Question

fing the probability of that a non leap year selected at random will contain 53sunday

Answer 1

Answer:

Step-by-step explanation:

We have 52 weeks and 2 days in a year . So we have 52 weeks means we have 52 Sundays .

And the rest of two days can be

Sunday, Monday

Monday , Tuesday

Tuesday, Wednesday

Wednesday, Thursday

Thursday, Friday

Friday, Saturday

Saturday, Sunday

By this we have probably 2 Sundays occuring so ,

Probability of 53 Sundays occuring is , Total outcomes are 7 and favourable are 2 so it's 2/7

I hope you'll get it clearly and if you have any queries so uh can reply to me

Answer 2

Answer is : 1 /7

total weeks in a non leap year = 52
total days in a non leap year = 365
i.e. 52*7= 364; One day is extra

Now, that extra day can be either Monday, Tuesday... Sunday
so, total probability = 7
possibility of Sunday = 1
therefore, probability = 1/7