fing the probability of that a non leap year selected at random will contain 53sunday
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Answer:
Step-by-step explanation:
We have 52 weeks and 2 days in a year . So we have 52 weeks means we have 52 Sundays .
And the rest of two days can be
Sunday, Monday
Monday , Tuesday
Tuesday, Wednesday
Wednesday, Thursday
Thursday, Friday
Friday, Saturday
Saturday, Sunday
By this we have probably 2 Sundays occuring so ,
Probability of 53 Sundays occuring is , Total outcomes are 7 and favourable are 2 so it's 2/7
I hope you'll get it clearly and if you have any queries so uh can reply to me
Answered by
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Answer is : 1 /7
total weeks in a non leap year = 52
total days in a non leap year = 365
i.e. 52*7= 364; One day is extra
Now, that extra day can be either Monday, Tuesday... Sunday
so, total probability = 7
possibility of Sunday = 1
therefore, probability = 1/7
total weeks in a non leap year = 52
total days in a non leap year = 365
i.e. 52*7= 364; One day is extra
Now, that extra day can be either Monday, Tuesday... Sunday
so, total probability = 7
possibility of Sunday = 1
therefore, probability = 1/7
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