Question

Fins a,b and c if the perimeter of the triangle is 36 cm and its sides are in ratio a:b:c=3:4:5

Answer 1

Step-by-step explanation:

Perimeter of the triangle = 36 cm

Ratio of the sides,

a : b : c = 3 : 4 : 5

To find : The lengths of sides a,b and c.

Let the sides be a(x), b(x) and c(x).

A/Q,

Perimeter of a triangle = Sum of all sides

=> 36 = (ax + bx + cx)

=> 36 = x (a + b + c)

=> 36 = x (3 + 4 + 5) ------->[from given]

=> 36 = x (12)

=> 36 = 12x

=> x = 3

Now,

Side a = a(x)

= 3×3

=9 cm

Side b = b(x)

= 4×3

= 12 cm

Side c = c(x)

= 5×3

= 15 cm

Therefore , Sides af the triangle are

9cm, 12cm and 15cm.

Answer 2

Step-by-step explanation:

let the sides of triangle be 3x, 4x and 5x

perimeter = sum of sides

⇒3x+4x+5x = 36cm

⇒12x = 36cm

⇒x = $\frac{36}{12}$

⇒x = 3

so the sides are 3×3 = 9cm, 4×3 = 12 cm, 5×3 = 15cm