Question

first pricipal the derivatives of 1÷x+3

Answer 1

Answer:f′(x)=limh→0f(x+h)−f(x)h  

ddx(1x3)=limh→01(x+h)3−1x3h=limh→0x3(x+h3)(1(x+h)3−1x3)x3(x+h)3⋅h=limh→0x3−(x+h)3x3(x+h)3⋅h=limh→0x3−(x3+3x2h+3xh2+h3)x3(x+h)3⋅h=limh→0−3x2h−3xh2−h3x3(x+h)3h=limh→0−h(3x2+3xh+h2)x3(x+h)3⋅h=limh→0−(3x2+3xh+h2)x3(x+h)3=−3x2x6=−3x4

Step-by-step explanation: