first second and fourth term of a preparation are respectively 5.2 3.9 and 3 find the third term
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a=5.2 and d= -1.3
we have to find 3rd term
Therefore a+(n-1)×d
a3= 5.2+(3-1)×(-1.3)
5.2+2×(-1.3)
5.2+(-2.6)
5.2-2.6
a3= 2.6
we have to find 3rd term
Therefore a+(n-1)×d
a3= 5.2+(3-1)×(-1.3)
5.2+2×(-1.3)
5.2+(-2.6)
5.2-2.6
a3= 2.6
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