Question

First term a and common differenced
given
Find first two terms of AP
a=-3 d = 4​

Answer 1

Given:-

⠀⠀⠀◍ First term (a) = -3

⠀⠀⠀◍ Common Difference (d) = 4

⠀

To Find:-

⠀⠀⠀◍ First two terms of an AP

⠀

Formula Used:-

⠀⠀⠀◍ For first term = a (already given)

⠀⠀⠀◍ For second term = a + d

⠀

Solution:-

⠀⠀⠀◍ First term = -3 (given)

⠀⠀⠀◍ Second term = a + d

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= -3 + 4

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 1

Answer:-

⠀⠀⠀★ First term of an AP = -3

⠀⠀⠀★ Seacond term of an AP = 1

Answer 2

Answer :-

{ A.P. = -3 , 1, 5 , 9 , 13 ... }

Given :-

a = -3

d = 4

Here ,

" a " = First term of an A.P

" d " = Common difference of an A.P

⠀

To Find :-

Write the A.P.

⠀

Calculations :-

As we all know the formula of finding an A.P .

Let's simply apply the formula here :-

$\large{\boxed{\bold{a_n\:=\:a + (n - 1)d}}}$

aₙ=a+(n-1)d

Second term

↠ a_2 = -3 + (2 - 1) × 4

↠ a_2 = - 3+ 1 × 4

↠ a_2 = -3 + 4

↠ a_2 = 1

Third term

↠ a_3 = -3 + ( 3 - 1 ) × 4

↠ a_3 = -3 + 2 × 4

↠ a_3 = -3 + 8

↠ a_3 = 5

⠀

Fourth term

↠ a_4 = -3 + ( 4 - 1 ) × 4

↠ a_4 = -3 + 3 × 4

↠ a_4 = -3 + 12

↠ a_4 = 9

Fifth term

↠ a_5 = -3 + ( 5 - 1 ) × 4

↠ a_5 = -3 + 4 × 4

↠ a_5 = -3 + 16

↠ a_5 = 13

A.P. = -3 , 1, 5 , 9 , 13 .....