Math, asked by rharshu55, 8 months ago

first term and common difference of an A.P are 6 and 3 respectively ;find S27

Answers

Answered by mayajakhar79

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Answer in 2 methods:

1st method:

since ,a=6 , d=3

we need to find S27=?

HERE, Sn=n/2{2a+{n-1}d}

=27/2{2×6+{27-1}3}

=27/2{12+26×3}

=27/2{90}

=27×45

=1215

hence sum to 27 terms is 1215

2nd method:

Given

a=6

n=27

d=3

S27=?

n=27

SOLUTION

S27=(n/2){2a+(n-1)d}

=(27/2){2(6)+(27-1)(3)}

=(27/2){12+26×3}

=(27/2)(12+78)

=(27/2)(90)

=13.5×90

=1215

ANSWER: Sn=1215

Step-by-step explanation:

Answered by jaideepnaidu2006

Answer:1188

Step-by-step explanation: a=6, d=3,n=27

sn=n/2[2a+(n-1)d]

s27=27/2[2(6)+(27-1)3]

=13.2[12+ 78]

=13.2[90]

=1188

therefore, the answer is 1188

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