Question

first term and common difference of an A.P are 6 and 3 respectively find S37?​

Answer 1

Answer:

Solution:

Given a = 6, d = 3

S37 = n/2 [2a+(n−1)d]

S37 = 37/2 [2×6+36×3]

= 37/2 [12+108]

= 37/2 [120]

= 18.5 × 120

= 2220

Hope this will help you....

If it's helpful to you then mark it as Brainliest and provide Thanks on my answer.....

Answer 2

answer:2220

a=6

d=3

S37=?

n=37

l=a+(n-1)d

=6+36×3

=6+108

=114

S37=n/2 (a+l)

=37/2 (6+114)

=37/2(120)

=37×60

=2220