Question

First term and common difference of an A.P. is 3 and 5, Find t20 =?

a = 3 , d = 5 , n = 20 , t20 = ?

tn = [ + ( n – 1 ) d ]

∴ t20 = [ 3 + ( – 1 ) x 5 ]

t20 = + 1 9 x 5

∴ t20 =​

Answer 1

Step-by-step explanation:

t20 = [a+(n-1)d]

= [3+(20-1)5]

= [3+(19)5]

=(3+95)

>t20 = 98

By:: Rahul SSC 10th