Question

First term and common different of an AP are 6and 3 respectively.find S27.

Answer 1

Answer:

a=first term = 6

d= common difference = 2

Sn = (n/2)[2a+(n-1) d]

S27 = (27/2)[2(6)+(27-1)3]

S27 = (27/2)[12+(26)(3)]

S27 = (27/2)[12+78]

S27 = (27/2)[90]

S27 = (27)*(45)

S27 = 1215

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