First three terms of an ap is 24 then the value of a is
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Let the three numbers in A.P. be a−d,a, and a+d
According to given information
Sum=(a−d)+(a)+(a+d)=24...(1)
⇒3a=24∴a=8
& Product=(a−d)a(a+d)=440...(2)
⇒(8−d)(8)(8+d)=440
⇒(8−d)(8+d)=55
⇒64−d
2
=55
⇒d
2
=64−55=9
⇒d=±3
Therefore when d=3, the numbers are 5,8,11 and
when d=−3, the numbers are 11,8 and 5.
Thus the three numbers are 5,8 and 11.
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