Question

first two numbers such that the sum of thrice the first and the second is 142 and four time the first exceeds the second by 138

Answer 1

Answer:40 and 22

Step-by-step explanation:

Let us assume, the two numbers are x and y.

Given:

3x + y = 142 ------------1

And also given:

4x – y = 138

y = 4x – 138 --------------2

Substitute the value of y from equation 2 in equation 1

3x + 4x – 138 = 142

7x - 138 = 142

7x = 142 + 138

7x = 280

x = 40

Therefore, y = (4 * 40) – 138 = 22

The two numbers are 40 and 22

Answer 2

first condition,
let the numbers be x& y
3x+3y=142
-4x+y=130
let we add both equations
we have to multiply eq.2 by 3 then it will be
-12x+3y=390