Question

five added to one third of a number gives twice the number.find the number

Answer 1

Let the number be a

According to question

5 + a/3 = 2a

=> (15+a)/3 = 2a

=> 15+a = 6a

=> 5a = 15

=> a = 3

Required number = 3

Answer 2

let the number is  x

then,

1/3 of x = x/3

5+x/3 = 2x

(15+x)/3 = 2x

15+x=6x

15= 6x-x

15= 5x

15/5 = x

3=x

then the number required here is 3