Five angles of 7 sides regular palygon are each 136°.
If the remaining 2 angles are equal Calculate the
size of each equal angles.
Answers
Answered by
10
Size of each equal angle of a polygon is 110°
Step-by-step explanation:
GIVEN
- 5 angles = 136° each
- 2 angles are equal
TO FIND
- Size of each equal angle of a polygon
___________________________
Let's take the angles as x°
We know that,
- 5 × 136° = Measures of Five angles
- 2 × x° = Measure of 2 equal angles
- 5 × 136° + 2 × x° = Sum of all interior angles of polygon
We know that,
- Sum of all interior angles of polygon = ( n - 2 ) × 180°
- Sum of all interior angles of polygon = ( 7 - 2 ) × 180°
- Sum of all interior angles of polygon = 5 × 180°
- Sum of all interior angles of polygon = 900°
We know that,
- 5 × 136° + 2 × x° = Sum of all interior angles of polygon
- 680° + 2x = 900°
- 2x = 900° - 680°
- 2x = 220° / 2
- x = 110°
x = 110°
Size of each equal angle of a polygon is 110°
Answered by
5
→ Answer :
5 angles = 136° each
2 angles are equal
TO FIND
Size of each equal angle of a polygon
___________________________
Let's take the angles as x°
We know that,
5 × 136° = Measures of Five angles
2 × x° = Measure of 2 equal angles
5 × 136° + 2 × x° = Sum of all interior angles of polygon
We know that,
Sum of all interior angles of polygon = ( n - 2 ) × 180°
Sum of all interior angles of polygon = ( 7 - 2 ) × 180°
Sum of all interior angles of polygon = 5 × 180°
Sum of all interior angles of polygon = 900°
We know that,
5 × 136° + 2 × x° = Sum of all interior angles of polygon
680° + 2x = 900°
2x = 900° - 680°
2x = 220° / 2
x = 110°
x = 110°
Size of each equal angle of a polygon is 110°
#BeBrainly
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