Question

five children had dinner. Chris ate more than Max. Brandon ate less than kate. Kate ate less than max but more than tanya. which child ate the second most?

Answer 1

Answer:

Max ate the second most.

Step-by-step explanation:

C>M

B<K

T<K<M

Putting it all into one big inequality

TorB<K<M<C

Chris, Max, Kate, Brandon/Tanya ate most to least (according to order of names).

Max ate the second most.

Answer 2

Answer:

I think that's Kate which ate second most bcs max ate more than Chris nd Kate so max is the first nd Kate ate more than Tanya nd some small amount Kate ate in comparison to mate nd Brandon .

I hope it helps