Question

Five cubes are placed adjacent to each other in a row. Find the ratio of the total surface

area of the cuboid thus formed to the total surface area of the three cubes​

Answer 1

Answer:

Given, three cube are placed adjacent in a row to form a cuboid.

Let the side of cube be a, three cube placed in row then breadth of cuboid be a, length of cuboid is 3a, height of cuboid is a.

Sum of total surface area of three cubes = 6a² + 6a² + 6a²

= 18a²

Total surface area of resulting cuboid =

2(lb + bh + 1h)

= 2(3a x a + axa + 3a xa)

= 2(7a²)

= 14a²

Ratio of total surface area of cuboid to

that of cube=

7:9

14a²

18a²

Open in answrapp >

C

7:9

79 9

Answer 2

Answer:

refer the attachment

Step-by-step explanation:

Five cubes are placed adjacent to each other in a row. Find the ratio of the total surface

area of the cuboid thus formed to the total surface area of the three cubes