Question

Five friends A, B, C, D and E played a game of dice. Each of them rolled 3 fair dice (bearing
numbers from 1 to 6), and added the three numbers to calculate their scores. The person
with the highest total won the game. It was additionally observed that:
• Each person had three different numbers on his three dice.
• No two people achieved the same total score.
• D, the person who achieved the lowest score rolled a 6.
. The total score of all the five friends was 55.
How much is the score of A. if A won the game?
1) 12
2) 13
3) 14
4) 15​

Answer 1

Step-by-step explanation:

4) 15 is the correct answer.

This question can be easily solved using logic or hit and trial

Here is an example of outcomes:

A: 15

B: 14

C: 13

D: 6

E: 7

@Usernametaken8

Answer 2

Step-by-step explanation:

Let's assume with the options that 15 is the highest and we've been given the lowest as 6 the total of 15+6 = 21 and the total scores is 55-21 = 34

Now we've to adjust 34 in the 3 players scores and were aware that no one got the same scores and can be adjusted in various ways to achieve 34 for example I have adjusted in 11,10 and 13 thus here the highest is 15.