Five men are employed for strawberry picking. They all don't pick strawberries at the same speed. They pick in the ratio of 1 :: 2 :: 3 :: 4 :: 5. That is, the second man picks 2 times as many strawberries as the first in the same amount of time, and the 3rd man picks 3 times as many strawberries as the first, and so on. To compensate for this, their manager makes the slower men work for more time. In fact, he makes them spend time in the ratio 5 :: 4 :: 3 :: 2 :: 1. That is, the first man works 5 times longer than the 5th man, and so on. At the end of the day, the manager realizes that they have not all picked the same amount of strawberries. Two men have picked 250 strawberies each. Two other men have picked more then these two. And one man has picked the maximum - more than anyone else. How many strawberries did this man pick?
Answers
Answer:
450
Step-by-step explanation:
The ratio of the picking speed of strawberries by the men are 1::2::3::4::5.
let the seed of 1st man be x per hour.
Therefore the speed of second man be 2x per hour.
Therefore the speed of third man be 3x per hour.
Therefore the speed of forth man be 4x per hour.
Therefore the speed of fifth man be 5x per hour.
Ratio of time spent by them is 5::4::3::2::1
let the time spent by 1st man be 5hour.
Therefore the time spent by second man is 4 hour.
Therefore the time spent by third man is 3 hour.
Therefore the time spent by forth man is 4 hour.
Therefore the time spent by fifth man be is 5 hour.
thus,
Total picking by 1st man=5x
Total picking by 2nd man=2x × 4=8x
Total picking by 3rd man=3x × 3=9x
Total picking by 4th man=4x × 2=8x
Total picking by 5th man=5x.
Now as per the question, picking of two person is 250 each and other two pick more then 250 and one person pick the maximum.
So we can say that the total picking of 1st and 5th person is 250 each.
Thus,
5x+5x=250×2
10X=500
x=50.
Therefore rate of picking is 50per hour.
The person who picks maximum, picks 9x.
Thus the total picking of that person is 9x=9×50=450.