Question

Five point charges each of charge q are placed at
vertices of regular Hexagon (one charge at one vertex),
the field at centre of hexagon is (a is side of hexagon)

Answer 1

Given info : Five point charges, each of charge q, are placed at vertices of regular hexagon (one charge at one vertex). side of hexagon is a.

To find : the field at centre of hexagon is..

solution : see figure, ABCDEF is a regular hexagon. five identical charges are placed at A, B , C , D and E as shown in figure.

here electric field due to B is cancelled by electric field due to E [ because equal and opposite vectors cancel each other ]

similarly, electric field due to A is cancelled by electric field due to D.

so remaining electric field = electric field due to C

Therefore net electric field = electric field due to C = kq/a² along OF

[ i.e., direction of electric field along the vertex where charge was not placed ]

Answer 2

Answer:

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