Five resistances are connected as shown in attachment. Find reading of ammeter
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in the triangle 2 , 3 ohm resistor are connected in series and 1 is in parallel due to direction of current . so add them up
3+3 = 6
and for parallel
1/R = 1/3 + 1/6= 1/2
so equivalent R of trangle is 2 ohm.
now the resultant 2 ohm resistor and 0.5 ohm resistor each are connected in series
so again add them
2+0.5 +0.5 = 3ohm
so total resistance is 3
current = voltage/ resistance
so current or reading of ammeter is 3/3 ampere
*1 ampere*
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