five resistors 2, 3, 4,5 and 6 ohm are connected in series to 6v battery. the current through 5 ohm resistor is
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In series combination, current through all resistors is same...
So to find that current we apply Ohm's law...
V=IR
Here R is 6+5+4+3+2 = 20ohms
V is 6 V
hence I is V/R = 0.3A
So to find that current we apply Ohm's law...
V=IR
Here R is 6+5+4+3+2 = 20ohms
V is 6 V
hence I is V/R = 0.3A
assanajay:
is we add first or we add only which are before them
If the resistors are in series, add all of them...
Feel free to ask
ok
send some numerical with solution from different chapter with formulas ay my whats no 8930003773
for cal or other exam
cgl
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